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130030543454245 = 5723161528625409
BaseRepresentation
bin11101100100001100011000…
…010110100100000000100101
3122001101210120010220112012221
4131210030120112210000211
5114020410023111013440
61140315112414112341
736250253040610150
oct3544143026440045
9561353503815187
10130030543454245
11384827099884a5
1212700959aab6b1
135772a9b408235
142417724870c97
1510075d5c70d4a
hex7643185a4025

130030543454245 has 16 divisors (see below), whose sum is σ = 186080976472320. Its totient is φ = 85287114215424.

The previous prime is 130030543454237. The next prime is 130030543454267. The reversal of 130030543454245 is 542454345030031.

It is a cyclic number.

It is not a de Polignac number, because 130030543454245 - 23 = 130030543454237 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80764311900 + ... + 80764313509.

It is an arithmetic number, because the mean of its divisors is an integer number (11630061029520).

Almost surely, 2130030543454245 is an apocalyptic number.

It is an amenable number.

130030543454245 is a deficient number, since it is larger than the sum of its proper divisors (56050433018075).

130030543454245 is a wasteful number, since it uses less digits than its factorization.

130030543454245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161528625444.

The product of its (nonzero) digits is 1728000, while the sum is 43.

Adding to 130030543454245 its reverse (542454345030031), we get a palindrome (672484888484276).

The spelling of 130030543454245 in words is "one hundred thirty trillion, thirty billion, five hundred forty-three million, four hundred fifty-four thousand, two hundred forty-five".

Divisors: 1 5 7 23 35 115 161 805 161528625409 807643127045 1130700377863 3715158384407 5653501889315 18575791922035 26006108690849 130030543454245