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130031210221133 = 1361613267493937
BaseRepresentation
bin11101100100001101000000…
…000110000100111001001101
3122001101212021121112210102212
4131210031000012010321031
5114020412404304034013
61140315302513200205
736250305415206014
oct3544150006047115
9561355247483385
10130031210221133
1138482a21299311
1212700b05260065
135772b765acb60
142417789237a7b
15100762457b6a8
hex764340184e4d

130031210221133 has 16 divisors (see below), whose sum is σ = 142561429244976. Its totient is φ = 117868527959040.

The previous prime is 130031210221109. The next prime is 130031210221189. The reversal of 130031210221133 is 331122012130031.

It can be written as a sum of positive squares in 8 ways, for example, as 38932832785924 + 91098377435209 = 6239618^2 + 9544547^2 .

It is a cyclic number.

It is not a de Polignac number, because 130031210221133 - 216 = 130031210155597 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130031210221099 and 130031210221108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130031210221433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 133260860 + ... + 134233077.

It is an arithmetic number, because the mean of its divisors is an integer number (8910089327811).

Almost surely, 2130031210221133 is an apocalyptic number.

130031210221133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

130031210221133 is a deficient number, since it is larger than the sum of its proper divisors (12530219023843).

130031210221133 is a wasteful number, since it uses less digits than its factorization.

130031210221133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267494624.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 130031210221133 its reverse (331122012130031), we get a palindrome (461153222351164).

The spelling of 130031210221133 in words is "one hundred thirty trillion, thirty-one billion, two hundred ten million, two hundred twenty-one thousand, one hundred thirty-three".

Divisors: 1 13 61 613 793 7969 37393 486109 267493937 3477421181 16317130157 163973783381 212122692041 2131659183953 10002400786241 130031210221133