130032021213301 has 4 divisors (see below), whose sum is σ = 130981160054412. Its totient is φ = 129082882372192.

The previous prime is 130032021213251. The next prime is 130032021213323. The reversal of 130032021213301 is 103312120230031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 114454585739025 + 15577435474276 = 10698345^2 + 3946826^2 .

It is a cyclic number.

It is not a de Polignac number, because 130032021213301 - 2¹⁵ = 130032021180533 is a prime.

It is a super-2 number, since 2×130032021213301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130032021213701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474569420350 + ... + 474569420623.

It is an arithmetic number, because the mean of its divisors is an integer number (32745290013603).

Almost surely, 2^{130032021213301} is an apocalyptic number.

It is an amenable number.

130032021213301 is a deficient number, since it is larger than the sum of its proper divisors (949138841111).

130032021213301 is an equidigital number, since it uses as much as digits as its factorization.

130032021213301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 949138841110.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 130032021213301 its reverse (103312120230031), we get a palindrome (233344141443332).

The spelling of 130032021213301 in words is "one hundred thirty trillion, thirty-two billion, twenty-one million, two hundred thirteen thousand, three hundred one".