1300320323233 has 4 divisors (see below), whose sum is σ = 1316780074240. Its totient is φ = 1283860572228.

The previous prime is 1300320323177. The next prime is 1300320323251. The reversal of 1300320323233 is 3323230230031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300320323233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300320323198 and 1300320323207.

It is not an unprimeable number, because it can be changed into a prime (1300320323293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8229875385 + ... + 8229875542.

It is an arithmetic number, because the mean of its divisors is an integer number (329195018560).

Almost surely, 2^{1300320323233} is an apocalyptic number.

It is an amenable number.

1300320323233 is a deficient number, since it is larger than the sum of its proper divisors (16459751007).

1300320323233 is an equidigital number, since it uses as much as digits as its factorization.

1300320323233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16459751006.

The product of its (nonzero) digits is 5832, while the sum is 25.

Adding to 1300320323233 its reverse (3323230230031), we get a palindrome (4623550553264).

The spelling of 1300320323233 in words is "one trillion, three hundred billion, three hundred twenty million, three hundred twenty-three thousand, two hundred thirty-three".