Base | Representation |
---|---|
bin | 11101100100001101110001… |
… | …100100101100001100111011 |
3 | 122001101221102110112200210022 |
4 | 131210031301210230030323 |
5 | 114020421104311030133 |
6 | 1140315521125241055 |
7 | 36250335115053425 |
oct | 3544156144541473 |
9 | 561357373480708 |
10 | 130032040330043 |
11 | 38483307924435 |
12 | 127010b726318b |
13 | 5772c79575467 |
14 | 241782759d815 |
15 | 100767239e998 |
hex | 76437192c33b |
130032040330043 has 4 divisors (see below), whose sum is σ = 130032124695528. Its totient is φ = 130031955964560.
The previous prime is 130032040330039. The next prime is 130032040330067. The reversal of 130032040330043 is 340033040230031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130032040330043 - 22 = 130032040330039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130032040329994 and 130032040330021.
It is not an unprimeable number, because it can be changed into a prime (130032040332043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39826946 + ... + 42968007.
It is an arithmetic number, because the mean of its divisors is an integer number (32508031173882).
Almost surely, 2130032040330043 is an apocalyptic number.
130032040330043 is a deficient number, since it is larger than the sum of its proper divisors (84365485).
130032040330043 is an equidigital number, since it uses as much as digits as its factorization.
130032040330043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84365484.
The product of its (nonzero) digits is 7776, while the sum is 26.
Adding to 130032040330043 its reverse (340033040230031), we get a palindrome (470065080560074).
The spelling of 130032040330043 in words is "one hundred thirty trillion, thirty-two billion, forty million, three hundred thirty thousand, forty-three".
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