Base | Representation |
---|---|
bin | 10010111011000001001… |
… | …111001010010010000011 |
3 | 11121022100200102211211221 |
4 | 102323001033022102003 |
5 | 132301024424202410 |
6 | 2433205411215511 |
7 | 162642123325435 |
oct | 22730117122203 |
9 | 4538320384757 |
10 | 1300322100355 |
11 | 461510a20a33 |
12 | 1900172a7597 |
13 | 95809a62675 |
14 | 46d16272655 |
15 | 23c5734c4da |
hex | 12ec13ca483 |
1300322100355 has 16 divisors (see below), whose sum is σ = 1705469900544. Its totient is φ = 947483274240.
The previous prime is 1300322100299. The next prime is 1300322100367. The reversal of 1300322100355 is 5530012230031.
It is not a de Polignac number, because 1300322100355 - 27 = 1300322100227 is a prime.
It is a super-2 number, since 2×13003221003552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 246737802 + ... + 246743071.
It is an arithmetic number, because the mean of its divisors is an integer number (106591868784).
Almost surely, 21300322100355 is an apocalyptic number.
1300322100355 is a deficient number, since it is larger than the sum of its proper divisors (405147800189).
1300322100355 is a wasteful number, since it uses less digits than its factorization.
1300322100355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 493480926.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 1300322100355 its reverse (5530012230031), we get a palindrome (6830334330386).
The spelling of 1300322100355 in words is "one trillion, three hundred billion, three hundred twenty-two million, one hundred thousand, three hundred fifty-five".
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