Base | Representation |
---|---|
bin | 111100100011010000… |
… | …1111001100011101111 |
3 | 110102122011201210022102 |
4 | 1321012201321203233 |
5 | 4112301232414021 |
6 | 135422551405315 |
7 | 12252215255045 |
oct | 1710641714357 |
9 | 412564653272 |
10 | 130032310511 |
11 | 50167938534 |
12 | 2124b68383b |
13 | c3537a838c |
14 | 64178ba395 |
15 | 35b0ae700b |
hex | 1e468798ef |
130032310511 has 4 divisors (see below), whose sum is σ = 130332616512. Its totient is φ = 129732004512.
The previous prime is 130032310483. The next prime is 130032310543. The reversal of 130032310511 is 115013230031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130032310511 - 210 = 130032309487 is a prime.
It is a super-2 number, since 2×1300323105112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032310571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150152351 + ... + 150153216.
It is an arithmetic number, because the mean of its divisors is an integer number (32583154128).
Almost surely, 2130032310511 is an apocalyptic number.
130032310511 is a deficient number, since it is larger than the sum of its proper divisors (300306001).
130032310511 is an equidigital number, since it uses as much as digits as its factorization.
130032310511 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300306000.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 130032310511 its reverse (115013230031), we get a palindrome (245045540542).
The spelling of 130032310511 in words is "one hundred thirty billion, thirty-two million, three hundred ten thousand, five hundred eleven".
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