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130032310511 = 433300305567
BaseRepresentation
bin111100100011010000…
…1111001100011101111
3110102122011201210022102
41321012201321203233
54112301232414021
6135422551405315
712252215255045
oct1710641714357
9412564653272
10130032310511
1150167938534
122124b68383b
13c3537a838c
1464178ba395
1535b0ae700b
hex1e468798ef

130032310511 has 4 divisors (see below), whose sum is σ = 130332616512. Its totient is φ = 129732004512.

The previous prime is 130032310483. The next prime is 130032310543. The reversal of 130032310511 is 115013230031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130032310511 - 210 = 130032309487 is a prime.

It is a super-2 number, since 2×1300323105112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130032310571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150152351 + ... + 150153216.

It is an arithmetic number, because the mean of its divisors is an integer number (32583154128).

Almost surely, 2130032310511 is an apocalyptic number.

130032310511 is a deficient number, since it is larger than the sum of its proper divisors (300306001).

130032310511 is an equidigital number, since it uses as much as digits as its factorization.

130032310511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300306000.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 130032310511 its reverse (115013230031), we get a palindrome (245045540542).

The spelling of 130032310511 in words is "one hundred thirty billion, thirty-two million, three hundred ten thousand, five hundred eleven".

Divisors: 1 433 300305567 130032310511