130032423244543 has 4 divisors (see below), whose sum is σ = 130034941791328. Its totient is φ = 130029904697760.

The previous prime is 130032423244513. The next prime is 130032423244573. The reversal of 130032423244543 is 345442324230031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (130032423244513) and next prime (130032423244573).

It is a cyclic number.

It is not a de Polignac number, because 130032423244543 - 2¹³ = 130032423236351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130032423244496 and 130032423244505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130032423244513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1259195946 + ... + 1259299207.

It is an arithmetic number, because the mean of its divisors is an integer number (32508735447832).

Almost surely, 2^{130032423244543} is an apocalyptic number.

130032423244543 is a deficient number, since it is larger than the sum of its proper divisors (2518546785).

130032423244543 is an equidigital number, since it uses as much as digits as its factorization.

130032423244543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2518546784.

The product of its (nonzero) digits is 829440, while the sum is 40.

Adding to 130032423244543 its reverse (345442324230031), we get a palindrome (475474747474574).

The spelling of 130032423244543 in words is "one hundred thirty trillion, thirty-two billion, four hundred twenty-three million, two hundred forty-four thousand, five hundred forty-three".