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130033004223 = 343344334741
BaseRepresentation
bin111100100011010010…
…0100010111010111111
3110102122020001000220110
41321012210202322333
54112301422113343
6135423014321103
712252224204403
oct1710644427277
9412566030813
10130033004223
1150168271751
122124b959193
13c35398c065
146417a1b103
1535b0bd2833
hex1e46922ebf

130033004223 has 4 divisors (see below), whose sum is σ = 173377338968. Its totient is φ = 86688669480.

The previous prime is 130033004201. The next prime is 130033004237. The reversal of 130033004223 is 322400330031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 130033004223 - 25 = 130033004191 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130033004223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130033004623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21672167368 + ... + 21672167373.

It is an arithmetic number, because the mean of its divisors is an integer number (43344334742).

Almost surely, 2130033004223 is an apocalyptic number.

130033004223 is a deficient number, since it is larger than the sum of its proper divisors (43344334745).

130033004223 is an equidigital number, since it uses as much as digits as its factorization.

130033004223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43344334744.

The product of its (nonzero) digits is 1296, while the sum is 21.

Adding to 130033004223 its reverse (322400330031), we get a palindrome (452433334254).

The spelling of 130033004223 in words is "one hundred thirty billion, thirty-three million, four thousand, two hundred twenty-three".

Divisors: 1 3 43344334741 130033004223