13003311221231 has 4 divisors (see below), whose sum is σ = 13003323318864. Its totient is φ = 13003299123600.

The previous prime is 13003311221221. The next prime is 13003311221237. The reversal of 13003311221231 is 13212211330031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13003311221231 - 2⁴² = 8605264710127 is a prime.

It is a super-2 number, since 2×13003311221231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13003311221197 and 13003311221206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003311221237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4260230 + ... + 6645011.

It is an arithmetic number, because the mean of its divisors is an integer number (3250830829716).

Almost surely, 2^{13003311221231} is an apocalyptic number.

13003311221231 is a deficient number, since it is larger than the sum of its proper divisors (12097633).

13003311221231 is a wasteful number, since it uses less digits than its factorization.

13003311221231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12097632.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13003311221231 its reverse (13212211330031), we get a palindrome (26215522551262).

The spelling of 13003311221231 in words is "thirteen trillion, three billion, three hundred eleven million, two hundred twenty-one thousand, two hundred thirty-one".