13003312013 has 4 divisors (see below), whose sum is σ = 13052754528. Its totient is φ = 12953869500.

The previous prime is 13003311911. The next prime is 13003312057. The reversal of 13003312013 is 31021330031.

13003312013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31021330031 = 4547 ⋅6822373.

It is a cyclic number.

It is not a de Polignac number, because 13003312013 - 2¹² = 13003307917 is a prime.

It is a super-2 number, since 2×13003312013² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13003311982 and 13003312000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003312313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24720863 + ... + 24721388.

It is an arithmetic number, because the mean of its divisors is an integer number (3263188632).

Almost surely, 2^13003312013 is an apocalyptic number.

It is an amenable number.

13003312013 is a deficient number, since it is larger than the sum of its proper divisors (49442515).

13003312013 is an equidigital number, since it uses as much as digits as its factorization.

13003312013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49442514.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13003312013 its reverse (31021330031), we get a palindrome (44024642044).

The spelling of 13003312013 in words is "thirteen billion, three million, three hundred twelve thousand, thirteen".