13003324045641 has 24 divisors (see below), whose sum is σ = 19479386463264. Its totient is φ = 8668368122400.

The previous prime is 13003324045619. The next prime is 13003324045717. The reversal of 13003324045641 is 14654042330031.

13003324045641 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 3 + 3 + 2 + 4 + 0 + 4 + 5 + 641 = 666.

It is not a de Polignac number, because 13003324045641 - 2¹⁴ = 13003324029257 is a prime.

It is a super-2 number, since 2×13003324045641² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13003324045596 and 13003324045605.

It is not an unprimeable number, because it can be changed into a prime (13003324045241) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2535966 + ... + 5695416.

It is an arithmetic number, because the mean of its divisors is an integer number (811641102636).

Almost surely, 2^{13003324045641} is an apocalyptic number.

It is an amenable number.

13003324045641 is a deficient number, since it is larger than the sum of its proper divisors (6476062417623).

13003324045641 is an equidigital number, since it uses as much as digits as its factorization.

13003324045641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3176403 (or 3176391 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 36.

Adding to 13003324045641 its reverse (14654042330031), we get a palindrome (27657366375672).

The spelling of 13003324045641 in words is "thirteen trillion, three billion, three hundred twenty-four million, forty-five thousand, six hundred forty-one".