Search a number
-
+
13003331233 = 49126483363
BaseRepresentation
bin11000001110000111…
…10001011010100001
31020120020001200001111
430013003301122201
5203112323044413
65550150303321
7640143330454
oct140703613241
936506050044
1013003331233
115573050242
12262a957b41
1312c2c9a049
148b4d9549b
155118add3d
hex3070f16a1

13003331233 has 4 divisors (see below), whose sum is σ = 13029815088. Its totient is φ = 12976847380.

The previous prime is 13003331197. The next prime is 13003331249. The reversal of 13003331233 is 33213330031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13003331233 - 233 = 4413396641 is a prime.

It is a super-2 number, since 2×130033312332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13003331333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13241191 + ... + 13242172.

It is an arithmetic number, because the mean of its divisors is an integer number (3257453772).

Almost surely, 213003331233 is an apocalyptic number.

It is an amenable number.

13003331233 is a deficient number, since it is larger than the sum of its proper divisors (26483855).

13003331233 is an equidigital number, since it uses as much as digits as its factorization.

13003331233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26483854.

The product of its (nonzero) digits is 1458, while the sum is 22.

Adding to 13003331233 its reverse (33213330031), we get a palindrome (46216661264).

The spelling of 13003331233 in words is "thirteen billion, three million, three hundred thirty-one thousand, two hundred thirty-three".

Divisors: 1 491 26483363 13003331233