Base | Representation |
---|---|
bin | 11000001110000111… |
… | …10001011001111101 |
3 | 1020120020001200000011 |
4 | 30013003301121331 |
5 | 203112323044242 |
6 | 5550150303221 |
7 | 640143330403 |
oct | 140703613175 |
9 | 36506050004 |
10 | 13003331197 |
11 | 557305020a |
12 | 262a957b11 |
13 | 12c2c9a01c |
14 | 8b4d95473 |
15 | 5118add17 |
hex | 3070f167d |
13003331197 has 2 divisors, whose sum is σ = 13003331198. Its totient is φ = 13003331196.
The previous prime is 13003331177. The next prime is 13003331249. The reversal of 13003331197 is 79113330031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12882023001 + 121308196 = 113499^2 + 11014^2 .
It is a cyclic number.
It is not a de Polignac number, because 13003331197 - 27 = 13003331069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13003331177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501665598 + 6501665599.
It is an arithmetic number, because the mean of its divisors is an integer number (6501665599).
Almost surely, 213003331197 is an apocalyptic number.
It is an amenable number.
13003331197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13003331197 is an equidigital number, since it uses as much as digits as its factorization.
13003331197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 31.
The spelling of 13003331197 in words is "thirteen billion, three million, three hundred thirty-one thousand, one hundred ninety-seven".
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