130033544445 has 72 divisors (see below), whose sum is σ = 262906136064. Its totient is φ = 59281564608.

The previous prime is 130033544437. The next prime is 130033544447. The reversal of 130033544445 is 544445330031.

130033544445 is a `hidden beast` number, since 130 + 0 + 33 + 54 + 4 + 445 = 666.

It is not a de Polignac number, because 130033544445 - 2³ = 130033544437 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130033544447) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 728892 + ... + 889578.

It is an arithmetic number, because the mean of its divisors is an integer number (3651474112).

Almost surely, 2^130033544445 is an apocalyptic number.

130033544445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

130033544445 is an abundant number, since it is smaller than the sum of its proper divisors (132872591619).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130033544445 is a wasteful number, since it uses less digits than its factorization.

130033544445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161079 (or 161069 counting only the distinct ones).

The product of its (nonzero) digits is 172800, while the sum is 36.

Adding to 130033544445 its reverse (544445330031), we get a palindrome (674478874476).

The spelling of 130033544445 in words is "one hundred thirty billion, thirty-three million, five hundred forty-four thousand, four hundred forty-five".