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1300335730115 = 5691376363453
BaseRepresentation
bin10010111011000010000…
…011001001110111000011
311121022101122002022100212
4102323002003021313003
5132301041421330430
62433211015304335
7162642350223362
oct22730203116703
94538348068325
101300335730115
114615186901a4
1219001b97b0ab
139580c825406
1446d17dbd7d9
1523c58640b95
hex12ec20c9dc3

1300335730115 has 8 divisors (see below), whose sum is σ = 1562661061008. Its totient is φ = 1038763127520.

The previous prime is 1300335730079. The next prime is 1300335730121. The reversal of 1300335730115 is 5110375330031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1300335730115 - 28 = 1300335729859 is a prime.

It is a super-2 number, since 2×13003357301152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188178272 + ... + 188185181.

It is an arithmetic number, because the mean of its divisors is an integer number (195332632626).

Almost surely, 21300335730115 is an apocalyptic number.

1300335730115 is a deficient number, since it is larger than the sum of its proper divisors (262325330893).

1300335730115 is an equidigital number, since it uses as much as digits as its factorization.

1300335730115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 376364149.

The product of its (nonzero) digits is 14175, while the sum is 32.

The spelling of 1300335730115 in words is "one trillion, three hundred billion, three hundred thirty-five million, seven hundred thirty thousand, one hundred fifteen".

Divisors: 1 5 691 3455 376363453 1881817265 260067146023 1300335730115