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130034002124 = 22132500653887
BaseRepresentation
bin111100100011010100…
…0010110100011001100
3110102122021220201202202
41321012220112203030
54112302201031444
6135423051541032
712252235531625
oct1710650264314
9412567821682
10130034002124
1150168893464
122125015a778
13c353c4b330
146417bdaa4c
1535b0d2d34e
hex1e46a168cc

130034002124 has 12 divisors (see below), whose sum is σ = 245064081024. Its totient is φ = 60015693264.

The previous prime is 130034002097. The next prime is 130034002193. The reversal of 130034002124 is 421200430031.

It is a super-2 number, since 2×1300340021242 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130034002096 and 130034002105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1250326892 + ... + 1250326995.

It is an arithmetic number, because the mean of its divisors is an integer number (20422006752).

Almost surely, 2130034002124 is an apocalyptic number.

It is an amenable number.

130034002124 is a deficient number, since it is larger than the sum of its proper divisors (115030078900).

130034002124 is a wasteful number, since it uses less digits than its factorization.

130034002124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2500653904 (or 2500653902 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 130034002124 its reverse (421200430031), we get a palindrome (551234432155).

The spelling of 130034002124 in words is "one hundred thirty billion, thirty-four million, two thousand, one hundred twenty-four".

Divisors: 1 2 4 13 26 52 2500653887 5001307774 10002615548 32508500531 65017001062 130034002124