130034240210051 has 4 divisors (see below), whose sum is σ = 130034340315600. Its totient is φ = 130034140104504.

The previous prime is 130034240210029. The next prime is 130034240210057. The reversal of 130034240210051 is 150012042430031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130034240210051 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130034240210051.

It is not an unprimeable number, because it can be changed into a prime (130034240210057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48078356 + ... + 50710913.

It is an arithmetic number, because the mean of its divisors is an integer number (32508585078900).

Almost surely, 2^{130034240210051} is an apocalyptic number.

130034240210051 is a deficient number, since it is larger than the sum of its proper divisors (100105549).

130034240210051 is an equidigital number, since it uses as much as digits as its factorization.

130034240210051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100105548.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 130034240210051 its reverse (150012042430031), we get a palindrome (280046282640082).

The spelling of 130034240210051 in words is "one hundred thirty trillion, thirty-four billion, two hundred forty million, two hundred ten thousand, fifty-one".