Base | Representation |
---|---|
bin | 111100100011010100… |
… | …1101001100010011001 |
3 | 110102122022120000001021 |
4 | 1321012221221202121 |
5 | 4112302242421131 |
6 | 135423103122441 |
7 | 12252241445632 |
oct | 1710651514231 |
9 | 412568500037 |
10 | 130034342041 |
11 | 50168aa588a |
12 | 212502a3421 |
13 | c354039c76 |
14 | 6417c88889 |
15 | 35b0d98e11 |
hex | 1e46a69899 |
130034342041 has 16 divisors (see below), whose sum is σ = 143998200000. Its totient is φ = 116926479936.
The previous prime is 130034342021. The next prime is 130034342051. The reversal of 130034342041 is 140243430031.
It is a de Polignac number, because none of the positive numbers 2k-130034342041 is a prime.
It is a super-2 number, since 2×1300343420412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130034341997 and 130034342015.
It is not an unprimeable number, because it can be changed into a prime (130034342021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1967466 + ... + 2032483.
It is an arithmetic number, because the mean of its divisors is an integer number (8999887500).
Almost surely, 2130034342041 is an apocalyptic number.
It is an amenable number.
130034342041 is a deficient number, since it is larger than the sum of its proper divisors (13963857959).
130034342041 is a wasteful number, since it uses less digits than its factorization.
130034342041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4000056.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 130034342041 its reverse (140243430031), we get a palindrome (270277772072).
The spelling of 130034342041 in words is "one hundred thirty billion, thirty-four million, three hundred forty-two thousand, forty-one".
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