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130034342041 = 1929593999949
BaseRepresentation
bin111100100011010100…
…1101001100010011001
3110102122022120000001021
41321012221221202121
54112302242421131
6135423103122441
712252241445632
oct1710651514231
9412568500037
10130034342041
1150168aa588a
12212502a3421
13c354039c76
146417c88889
1535b0d98e11
hex1e46a69899

130034342041 has 16 divisors (see below), whose sum is σ = 143998200000. Its totient is φ = 116926479936.

The previous prime is 130034342021. The next prime is 130034342051. The reversal of 130034342041 is 140243430031.

It is a de Polignac number, because none of the positive numbers 2k-130034342041 is a prime.

It is a super-2 number, since 2×1300343420412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130034341997 and 130034342015.

It is not an unprimeable number, because it can be changed into a prime (130034342021) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1967466 + ... + 2032483.

It is an arithmetic number, because the mean of its divisors is an integer number (8999887500).

Almost surely, 2130034342041 is an apocalyptic number.

It is an amenable number.

130034342041 is a deficient number, since it is larger than the sum of its proper divisors (13963857959).

130034342041 is a wasteful number, since it uses less digits than its factorization.

130034342041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4000056.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 130034342041 its reverse (140243430031), we get a palindrome (270277772072).

The spelling of 130034342041 in words is "one hundred thirty billion, thirty-four million, three hundred forty-two thousand, forty-one".

Divisors: 1 19 29 59 551 1121 1711 32509 3999949 75999031 115998521 235996991 2203971899 4483942829 6843912739 130034342041