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130034344135 = 583313335769
BaseRepresentation
bin111100100011010100…
…1101010000011000111
3110102122022120002220211
41321012221222003013
54112302243003020
6135423103140251
712252241455013
oct1710651520307
9412568502824
10130034344135
1150168aa7413
12212502a4687
13c35403abc7
146417c89543
1535b0d9985a
hex1e46a6a0c7

130034344135 has 8 divisors (see below), whose sum is σ = 157921228080. Its totient is φ = 102774131904.

The previous prime is 130034344117. The next prime is 130034344159. The reversal of 130034344135 is 531443430031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130034344135 - 25 = 130034344103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130034344097 and 130034344106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 156667470 + ... + 156668299.

It is an arithmetic number, because the mean of its divisors is an integer number (19740153510).

Almost surely, 2130034344135 is an apocalyptic number.

130034344135 is a deficient number, since it is larger than the sum of its proper divisors (27886883945).

130034344135 is an equidigital number, since it uses as much as digits as its factorization.

130034344135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 313335857.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 130034344135 its reverse (531443430031), we get a palindrome (661477774166).

The spelling of 130034344135 in words is "one hundred thirty billion, thirty-four million, three hundred forty-four thousand, one hundred thirty-five".

Divisors: 1 5 83 415 313335769 1566678845 26006868827 130034344135