Base | Representation |
---|---|
bin | 10010111011000010111… |
… | …010001010110101101101 |
3 | 11121022102122020000112102 |
4 | 102323002322022311231 |
5 | 132301104114331140 |
6 | 2433212252344445 |
7 | 162642613631000 |
oct | 22730272126555 |
9 | 4538378200472 |
10 | 1300350152045 |
11 | 46152584064a |
12 | 190024775125 |
13 | 958128048b9 |
14 | 46d19c95537 |
15 | 23c59a3de15 |
hex | 12ec2e8ad6d |
1300350152045 has 16 divisors (see below), whose sum is σ = 1819731993600. Its totient is φ = 891668674512.
The previous prime is 1300350152029. The next prime is 1300350152063. The reversal of 1300350152045 is 5402510530031.
It is not a de Polignac number, because 1300350152045 - 24 = 1300350152029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300350151999 and 1300350152017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 379109117 + ... + 379112546.
It is an arithmetic number, because the mean of its divisors is an integer number (113733249600).
Almost surely, 21300350152045 is an apocalyptic number.
It is an amenable number.
1300350152045 is a deficient number, since it is larger than the sum of its proper divisors (519381841555).
1300350152045 is an frugal number, since it uses more digits than its factorization.
1300350152045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 758221689 (or 758221675 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 1300350152045 its reverse (5402510530031), we get a palindrome (6702860682076).
The spelling of 1300350152045 in words is "one trillion, three hundred billion, three hundred fifty million, one hundred fifty-two thousand, forty-five".
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