Search a number
-
+
130035049 = 314194679
BaseRepresentation
bin1111100000000…
…10110101101001
3100001200110112221
413300002311221
5231242110144
620523034041
73136164634
oct760026551
9301613487
10130035049
1167446291
123766b921
1320c2b721
14133acc1b
15b638d84
hex7c02d69

130035049 has 4 divisors (see below), whose sum is σ = 134229760. Its totient is φ = 125840340.

The previous prime is 130035047. The next prime is 130035071. The reversal of 130035049 is 940530031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130035049 - 21 = 130035047 is a prime.

It is a super-2 number, since 2×1300350492 = 33818227936864802, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130035047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2097309 + ... + 2097370.

It is an arithmetic number, because the mean of its divisors is an integer number (33557440).

Almost surely, 2130035049 is an apocalyptic number.

It is an amenable number.

130035049 is a deficient number, since it is larger than the sum of its proper divisors (4194711).

130035049 is an equidigital number, since it uses as much as digits as its factorization.

130035049 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4194710.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 130035049 is about 11403.2911477345. The cubic root of 130035049 is about 506.6252237475.

The spelling of 130035049 in words is "one hundred thirty million, thirty-five thousand, forty-nine".

Divisors: 1 31 4194679 130035049