Base | Representation |
---|---|
bin | 11101100100010001100000… |
… | …111101010111111000101111 |
3 | 122001102022210100210001202211 |
4 | 131210101200331113320233 |
5 | 114021002320434230210 |
6 | 1140321423435031251 |
7 | 36250536463314310 |
oct | 3544214075277057 |
9 | 561368710701684 |
10 | 130036056555055 |
11 | 38484a8898a762 |
12 | 12701a3829b527 |
13 | 5773469657c71 |
14 | 2417ac8b38607 |
15 | 1007809c7c38a |
hex | 764460f57e2f |
130036056555055 has 16 divisors (see below), whose sum is σ = 178442400374784. Its totient is φ = 89113963088160.
The previous prime is 130036056555043. The next prime is 130036056555121. The reversal of 130036056555055 is 550555650630031.
It is not a de Polignac number, because 130036056555055 - 215 = 130036056522287 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1116994081 + ... + 1117110490.
It is an arithmetic number, because the mean of its divisors is an integer number (11152650023424).
Almost surely, 2130036056555055 is an apocalyptic number.
130036056555055 is a deficient number, since it is larger than the sum of its proper divisors (48406343819729).
130036056555055 is a wasteful number, since it uses less digits than its factorization.
130036056555055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2234106246.
The product of its (nonzero) digits is 5062500, while the sum is 49.
The spelling of 130036056555055 in words is "one hundred thirty trillion, thirty-six billion, fifty-six million, five hundred fifty-five thousand, fifty-five".
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