13004014101 has 12 divisors (see below), whose sum is σ = 18775027008. Its totient is φ = 8002469904.

The previous prime is 13004014087. The next prime is 13004014103. The reversal of 13004014101 is 10141040031.

It is not a de Polignac number, because 13004014101 - 2⁵ = 13004014069 is a prime.

It is a super-3 number, since 3×13004014101³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004014103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12823965 + ... + 12824978.

It is an arithmetic number, because the mean of its divisors is an integer number (1564585584).

Almost surely, 2^13004014101 is an apocalyptic number.

It is an amenable number.

13004014101 is a deficient number, since it is larger than the sum of its proper divisors (5771012907).

13004014101 is a wasteful number, since it uses less digits than its factorization.

13004014101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25648972 (or 25648959 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13004014101 its reverse (10141040031), we get a palindrome (23145054132).

The spelling of 13004014101 in words is "thirteen billion, four million, fourteen thousand, one hundred one".