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13004014403 = 412711170373
BaseRepresentation
bin11000001110001100…
…11000001101000011
31020120021100101012002
430013012120031003
5203113011430103
65550213054215
7640152204302
oct140706301503
936507311162
1013004014403
115573477546
12262b02736b
1312c3178ca3
148b50d2439
15511996488
hex307198343

13004014403 has 8 divisors (see below), whose sum is σ = 13370352576. Its totient is φ = 12640017600.

The previous prime is 13004014399. The next prime is 13004014417. The reversal of 13004014403 is 30441040031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004014403 - 22 = 13004014399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004014453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 574076 + ... + 596297.

It is an arithmetic number, because the mean of its divisors is an integer number (1671294072).

Almost surely, 213004014403 is an apocalyptic number.

13004014403 is a deficient number, since it is larger than the sum of its proper divisors (366338173).

13004014403 is a wasteful number, since it uses less digits than its factorization.

13004014403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1170685.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13004014403 its reverse (30441040031), we get a palindrome (43445054434).

The spelling of 13004014403 in words is "thirteen billion, four million, fourteen thousand, four hundred three".

Divisors: 1 41 271 11111 1170373 47985293 317171083 13004014403