130040317 has 4 divisors (see below), whose sum is σ = 141862176. Its totient is φ = 118218460.

The previous prime is 130040297. The next prime is 130040341. The reversal of 130040317 is 713040031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 713040031 = 11 ⋅64821821.

It is a cyclic number.

It is not a de Polignac number, because 130040317 - 2¹¹ = 130038269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130040294 and 130040303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130040347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5910913 + ... + 5910934.

It is an arithmetic number, because the mean of its divisors is an integer number (35465544).

Almost surely, 2^130040317 is an apocalyptic number.

It is an amenable number.

130040317 is a deficient number, since it is larger than the sum of its proper divisors (11821859).

130040317 is a wasteful number, since it uses less digits than its factorization.

130040317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11821858.

The product of its (nonzero) digits is 252, while the sum is 19.

The square root of 130040317 is about 11403.5221313417. The cubic root of 130040317 is about 506.6320651482.

Adding to 130040317 its reverse (713040031), we get a palindrome (843080348).

The spelling of 130040317 in words is "one hundred thirty million, forty thousand, three hundred seventeen".