1300404133001 has 32 divisors (see below), whose sum is σ = 1343413911840. Its totient is φ = 1258293657600.

The previous prime is 1300404132959. The next prime is 1300404133043. The reversal of 1300404133001 is 1003314040031.

It is an interprime number because it is at equal distance from previous prime (1300404132959) and next prime (1300404133043).

It can be written as a sum of positive squares in 16 ways, for example, as 1093856607376 + 206547525625 = 1045876^2 + 454475^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300404133001 - 2²⁶ = 1300337024137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300404133601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1258861181 + ... + 1258862213.

It is an arithmetic number, because the mean of its divisors is an integer number (41981684745).

Almost surely, 2^{1300404133001} is an apocalyptic number.

It is an amenable number.

1300404133001 is a deficient number, since it is larger than the sum of its proper divisors (43009778839).

1300404133001 is a wasteful number, since it uses less digits than its factorization.

1300404133001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2397.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1300404133001 its reverse (1003314040031), we get a palindrome (2303718173032).

The spelling of 1300404133001 in words is "one trillion, three hundred billion, four hundred four million, one hundred thirty-three thousand, one".