130041252000 has 576 divisors, whose sum is σ = 505234050048. Its totient is φ = 31415040000.

The previous prime is 130041251969. The next prime is 130041252001. The reversal of 130041252000 is 252140031.

130041252000 is a `hidden beast` number, since 130 + 0 + 4 + 12 + 520 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (130041252001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 214235697 + ... + 214236303.

It is an arithmetic number, because the mean of its divisors is an integer number (877142448).

Almost surely, 2^130041252000 is an apocalyptic number.

130041252000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130041252000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (252617025024).

130041252000 is an abundant number, since it is smaller than the sum of its proper divisors (375192798048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130041252000 is a wasteful number, since it uses less digits than its factorization.

130041252000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1190 (or 1169 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 18.

Adding to 130041252000 its reverse (252140031), we get a palindrome (130293392031).

The spelling of 130041252000 in words is "one hundred thirty billion, forty-one million, two hundred fifty-two thousand".