130042025 has 6 divisors (see below), whose sum is σ = 161252142. Its totient is φ = 104033600.

The previous prime is 130042021. The next prime is 130042039. The reversal of 130042025 is 520240031.

It can be written as a sum of positive squares in 3 ways, for example, as 8976016 + 121066009 = 2996^2 + 11003^2 .

It is not a de Polignac number, because 130042025 - 2² = 130042021 is a prime.

It is a super-2 number, since 2×130042025² = 33821856532201250, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130041994 and 130042012.

It is not an unprimeable number, because it can be changed into a prime (130042021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2600816 + ... + 2600865.

It is an arithmetic number, because the mean of its divisors is an integer number (26875357).

Almost surely, 2^130042025 is an apocalyptic number.

It is an amenable number.

130042025 is a deficient number, since it is larger than the sum of its proper divisors (31210117).

130042025 is an equidigital number, since it uses as much as digits as its factorization.

130042025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5201691 (or 5201686 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 130042025 is about 11403.5970202388. The cubic root of 130042025 is about 506.6342832392.

Adding to 130042025 its reverse (520240031), we get a palindrome (650282056).

The spelling of 130042025 in words is "one hundred thirty million, forty-two thousand, twenty-five".