130042202200033 has 4 divisors (see below), whose sum is σ = 130074607437588. Its totient is φ = 130009796962480.

The previous prime is 130042202199967. The next prime is 130042202200093. The reversal of 130042202200033 is 330002202240031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47286210991009 + 82755991209024 = 6876497^2 + 9097032^2 .

It is a cyclic number.

It is not a de Polignac number, because 130042202200033 - 2⁴⁵ = 94857830111201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130042202199977 and 130042202200013.

It is not an unprimeable number, because it can be changed into a prime (130042202200093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16202612758 + ... + 16202620783.

It is an arithmetic number, because the mean of its divisors is an integer number (32518651859397).

Almost surely, 2^{130042202200033} is an apocalyptic number.

It is an amenable number.

130042202200033 is a deficient number, since it is larger than the sum of its proper divisors (32405237555).

130042202200033 is an equidigital number, since it uses as much as digits as its factorization.

130042202200033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32405237554.

The product of its (nonzero) digits is 1728, while the sum is 22.

Adding to 130042202200033 its reverse (330002202240031), we get a palindrome (460044404440064).

The spelling of 130042202200033 in words is "one hundred thirty trillion, forty-two billion, two hundred two million, two hundred thousand, thirty-three".