13004231400241 has 4 divisors (see below), whose sum is σ = 13224642102000. Its totient is φ = 12783820698484.

The previous prime is 13004231400227. The next prime is 13004231400263. The reversal of 13004231400241 is 14200413240031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13004231400241 - 2³⁹ = 12454475586353 is a prime.

It is a super-2 number, since 2×13004231400241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004235400241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110205350791 + ... + 110205350908.

It is an arithmetic number, because the mean of its divisors is an integer number (3306160525500).

Almost surely, 2^{13004231400241} is an apocalyptic number.

It is an amenable number.

13004231400241 is a deficient number, since it is larger than the sum of its proper divisors (220410701759).

13004231400241 is an equidigital number, since it uses as much as digits as its factorization.

13004231400241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220410701758.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13004231400241 its reverse (14200413240031), we get a palindrome (27204644640272).

The spelling of 13004231400241 in words is "thirteen trillion, four billion, two hundred thirty-one million, four hundred thousand, two hundred forty-one".