1300423210321 has 27 divisors (see below), whose sum is σ = 1403390563419. Its totient is φ = 1204823326608.

The previous prime is 1300423210319. The next prime is 1300423210381. The reversal of 1300423210321 is 1230123240031.

The square root of 1300423210321 is 1140361.

It is a perfect power (a square), and thus also a powerful number.

It can be written as a sum of positive squares in only one way, i.e., 854247305025 + 446175905296 = 924255^2 + 667964^2 .

It is not a de Polignac number, because 1300423210321 - 2¹ = 1300423210319 is a prime.

It is a super-2 number, since 2×1300423210321² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300423210292 and 1300423210301.

It is not an unprimeable number, because it can be changed into a prime (1300423210381) by changing a digit.

It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 1018341735 + ... + 1018343011.

Almost surely, 2^{1300423210321} is an apocalyptic number.

1300423210321 is the 1140361-st square number.

1300423210321 is the 570181-st centered octagonal number.

It is an amenable number.

1300423210321 is a deficient number, since it is larger than the sum of its proper divisors (102967353098).

1300423210321 is an frugal number, since it uses more digits than its factorization.

1300423210321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2686 (or 1343 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 1300423210321 its reverse (1230123240031), we get a palindrome (2530546450352).

The spelling of 1300423210321 in words is "one trillion, three hundred billion, four hundred twenty-three million, two hundred ten thousand, three hundred twenty-one".