Base | Representation |
---|---|
bin | 100110110000010… |
… | …1110100110001111 |
3 | 10100121222102212201 |
4 | 1031200232212033 |
5 | 10130402100403 |
6 | 333012342331 |
7 | 44140300555 |
oct | 11540564617 |
9 | 3317872781 |
10 | 1300425103 |
11 | 60806869a |
12 | 3036149a7 |
13 | 179556613 |
14 | c49d1bd5 |
15 | 7927621d |
hex | 4d82e98f |
1300425103 has 4 divisors (see below), whose sum is σ = 1301757120. Its totient is φ = 1299093088.
The previous prime is 1300425101. The next prime is 1300425109. The reversal of 1300425103 is 3015240031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1300425103 - 21 = 1300425101 is a prime.
It is a super-2 number, since 2×13004251032 = 3382210897025121218, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300425101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 664543 + ... + 666496.
It is an arithmetic number, because the mean of its divisors is an integer number (325439280).
Almost surely, 21300425103 is an apocalyptic number.
1300425103 is a deficient number, since it is larger than the sum of its proper divisors (1332017).
1300425103 is an equidigital number, since it uses as much as digits as its factorization.
1300425103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1332016.
The product of its (nonzero) digits is 360, while the sum is 19.
The square root of 1300425103 is about 36061.4073907273. The cubic root of 1300425103 is about 1091.5118327602.
Adding to 1300425103 its reverse (3015240031), we get a palindrome (4315665134).
The spelling of 1300425103 in words is "one billion, three hundred million, four hundred twenty-five thousand, one hundred three".
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