Base | Representation |
---|---|
bin | 11000001110001110… |
… | …11110110001010001 |
3 | 1020120021220001200012 |
4 | 30013013132301101 |
5 | 203113100202231 |
6 | 5550223204305 |
7 | 640154520053 |
oct | 140707366121 |
9 | 36507801605 |
10 | 13004303441 |
11 | 5573654718 |
12 | 262b146695 |
13 | 12c324a70c |
14 | 8b51698d3 |
15 | 511a01e2b |
hex | 3071dec51 |
13004303441 has 8 divisors (see below), whose sum is σ = 13154157000. Its totient is φ = 12854533120.
The previous prime is 13004303407. The next prime is 13004303443. The reversal of 13004303441 is 14430340031.
13004303441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 3930788416 + 9073515025 = 62696^2 + 95255^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004303441 is a prime.
It is a super-2 number, since 2×130043034412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13004303443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 326585 + ... + 364233.
It is an arithmetic number, because the mean of its divisors is an integer number (1644269625).
Almost surely, 213004303441 is an apocalyptic number.
It is an amenable number.
13004303441 is a deficient number, since it is larger than the sum of its proper divisors (149853559).
13004303441 is an equidigital number, since it uses as much as digits as its factorization.
13004303441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41619.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13004303441 its reverse (14430340031), we get a palindrome (27434643472).
The spelling of 13004303441 in words is "thirteen billion, four million, three hundred three thousand, four hundred forty-one".
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