Base | Representation |
---|---|
bin | 11000001110001110… |
… | …11110110000101111 |
3 | 1020120021220001121221 |
4 | 30013013132300233 |
5 | 203113100202112 |
6 | 5550223204211 |
7 | 640154520004 |
oct | 140707366057 |
9 | 36507801557 |
10 | 13004303407 |
11 | 5573654697 |
12 | 262b146667 |
13 | 12c324a6b4 |
14 | 8b51698ab |
15 | 511a01e07 |
hex | 3071dec2f |
13004303407 has 2 divisors, whose sum is σ = 13004303408. Its totient is φ = 13004303406.
The previous prime is 13004303393. The next prime is 13004303443. The reversal of 13004303407 is 70430340031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13004303407 - 215 = 13004270639 is a prime.
It is a super-2 number, since 2×130043034072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004303447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502151703 + 6502151704.
It is an arithmetic number, because the mean of its divisors is an integer number (6502151704).
Almost surely, 213004303407 is an apocalyptic number.
13004303407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004303407 is an equidigital number, since it uses as much as digits as its factorization.
13004303407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 25.
Adding to 13004303407 its reverse (70430340031), we get a palindrome (83434643438).
The spelling of 13004303407 in words is "thirteen billion, four million, three hundred three thousand, four hundred seven".
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