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130043124235 = 526008624847
BaseRepresentation
bin111100100011100101…
…1001001101000001011
3110102122221002011221201
41321013023021220023
54112312014433420
6135424015245031
712252406213663
oct1710713115013
9412587064851
10130043124235
1150172a53aa2
1221253219777
13c355ac342b
1464190d31a3
1535b1a3110a
hex1e472c9a0b

130043124235 has 4 divisors (see below), whose sum is σ = 156051749088. Its totient is φ = 104034499384.

The previous prime is 130043124223. The next prime is 130043124257. The reversal of 130043124235 is 532421340031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130043124235 - 29 = 130043123723 is a prime.

It is a super-2 number, since 2×1300431242352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13004312419 + ... + 13004312428.

It is an arithmetic number, because the mean of its divisors is an integer number (39012937272).

Almost surely, 2130043124235 is an apocalyptic number.

130043124235 is a deficient number, since it is larger than the sum of its proper divisors (26008624853).

130043124235 is an equidigital number, since it uses as much as digits as its factorization.

130043124235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26008624852.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130043124235 its reverse (532421340031), we get a palindrome (662464464266).

The spelling of 130043124235 in words is "one hundred thirty billion, forty-three million, one hundred twenty-four thousand, two hundred thirty-five".

Divisors: 1 5 26008624847 130043124235