Base | Representation |
---|---|
bin | 11101100100011000010111… |
… | …010010000100001100000001 |
3 | 122001110000202212100002120110 |
4 | 131210120113102010030001 |
5 | 114021112401030300001 |
6 | 1140325041253301533 |
7 | 36251216640053430 |
oct | 3544302722041401 |
9 | 561400685302513 |
10 | 130043410400001 |
11 | 38488111a4526a |
12 | 1270334b0348a9 |
13 | 577406c0621c7 |
14 | 24181c5683117 |
15 | 1007ada68e3d6 |
hex | 764617484301 |
130043410400001 has 32 divisors (see below), whose sum is σ = 202996007827200. Its totient is φ = 72497562808320.
The previous prime is 130043410399999. The next prime is 130043410400081. The reversal of 130043410400001 is 100004014340031.
It is not a de Polignac number, because 130043410400001 - 21 = 130043410399999 is a prime.
It is a super-2 number, since 2×1300434104000012 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (130043410400081) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 146935315 + ... + 147817703.
It is an arithmetic number, because the mean of its divisors is an integer number (6343625244600).
Almost surely, 2130043410400001 is an apocalyptic number.
It is an amenable number.
130043410400001 is a deficient number, since it is larger than the sum of its proper divisors (72952597427199).
130043410400001 is a wasteful number, since it uses less digits than its factorization.
130043410400001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1053609.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 130043410400001 its reverse (100004014340031), we get a palindrome (230047424740032).
The spelling of 130043410400001 in words is "one hundred thirty trillion, forty-three billion, four hundred ten million, four hundred thousand, one".
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