13004342101 has 4 divisors (see below), whose sum is σ = 13005000000. Its totient is φ = 13003684204.

The previous prime is 13004342089. The next prime is 13004342167. The reversal of 13004342101 is 10124340031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13004342101 - 2⁵ = 13004342069 is a prime.

It is a super-2 number, since 2×13004342101² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004342171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298351 + ... + 339148.

It is an arithmetic number, because the mean of its divisors is an integer number (3251250000).

Almost surely, 2^13004342101 is an apocalyptic number.

It is an amenable number.

13004342101 is a deficient number, since it is larger than the sum of its proper divisors (657899).

13004342101 is an equidigital number, since it uses as much as digits as its factorization.

13004342101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 657898.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13004342101 its reverse (10124340031), we get a palindrome (23128682132).

The spelling of 13004342101 in words is "thirteen billion, four million, three hundred forty-two thousand, one hundred one".