Base | Representation |
---|---|
bin | 11101100100011000101001… |
… | …001001100100010110000010 |
3 | 122001110001112202101121011001 |
4 | 131210120221021210112002 |
5 | 114021114004300143211 |
6 | 1140325131122242214 |
7 | 36251230240023133 |
oct | 3544305111442602 |
9 | 561401482347131 |
10 | 130043710162306 |
11 | 38488256177106 |
12 | 127034134b636a |
13 | 57740b91a8a55 |
14 | 24182133d3c8a |
15 | 1007b06b52ac1 |
hex | 764629264582 |
130043710162306 has 4 divisors (see below), whose sum is σ = 195065565243462. Its totient is φ = 65021855081152.
The previous prime is 130043710162297. The next prime is 130043710162307. The reversal of 130043710162306 is 603261017340031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 117288705060081 + 12755005102225 = 10829991^2 + 3571415^2 .
It is a super-2 number, since 2×1300437101623062 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130043710162307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32510927540575 + ... + 32510927540578.
Almost surely, 2130043710162306 is an apocalyptic number.
130043710162306 is a deficient number, since it is larger than the sum of its proper divisors (65021855081156).
130043710162306 is an equidigital number, since it uses as much as digits as its factorization.
130043710162306 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65021855081155.
The product of its (nonzero) digits is 54432, while the sum is 37.
The spelling of 130043710162306 in words is "one hundred thirty trillion, forty-three billion, seven hundred ten million, one hundred sixty-two thousand, three hundred six".
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