1300440041101 has 8 divisors (see below), whose sum is σ = 1323404785664. Its totient is φ = 1277674125840.

The previous prime is 1300440041083. The next prime is 1300440041161. The reversal of 1300440041101 is 1011400440031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300440041101 - 2¹⁵ = 1300440008333 is a prime.

It is a super-2 number, since 2×1300440041101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300440041161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49694130 + ... + 49720291.

It is an arithmetic number, because the mean of its divisors is an integer number (165425598208).

Almost surely, 2^{1300440041101} is an apocalyptic number.

It is an amenable number.

1300440041101 is a deficient number, since it is larger than the sum of its proper divisors (22964744563).

1300440041101 is a wasteful number, since it uses less digits than its factorization.

1300440041101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99414651.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1300440041101 its reverse (1011400440031), we get a palindrome (2311840481132).

The spelling of 1300440041101 in words is "one trillion, three hundred billion, four hundred forty million, forty-one thousand, one hundred one".