Base | Representation |
---|---|
bin | 11000001110001111… |
… | …11001101001110011 |
3 | 1020120022002122201111 |
4 | 30013013321221303 |
5 | 203113112213210 |
6 | 5550225414151 |
7 | 640155456100 |
oct | 140707715163 |
9 | 36508078644 |
10 | 13004413555 |
11 | 557371a421 |
12 | 262b19a357 |
13 | 12c3288883 |
14 | 8b5197aa7 |
15 | 511a2488a |
hex | 3071f9a73 |
13004413555 has 48 divisors (see below), whose sum is σ = 18981492480. Its totient is φ = 8511991488.
The previous prime is 13004413519. The next prime is 13004413573. The reversal of 13004413555 is 55531440031.
It is not a de Polignac number, because 13004413555 - 219 = 13003889267 is a prime.
It is a super-2 number, since 2×130044135552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3080236 + ... + 3084454.
It is an arithmetic number, because the mean of its divisors is an integer number (395447760).
Almost surely, 213004413555 is an apocalyptic number.
13004413555 is a deficient number, since it is larger than the sum of its proper divisors (5977078925).
13004413555 is a wasteful number, since it uses less digits than its factorization.
13004413555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4808 (or 4801 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13004413555 its reverse (55531440031), we get a palindrome (68535853586).
The spelling of 13004413555 in words is "thirteen billion, four million, four hundred thirteen thousand, five hundred fifty-five".
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