Base | Representation |
---|---|
bin | 11000001110001111… |
… | …11011010001111111 |
3 | 1020120022002222212110 |
4 | 30013013323101333 |
5 | 203113112421343 |
6 | 5550225505103 |
7 | 640155514404 |
oct | 140707732177 |
9 | 36508088773 |
10 | 13004420223 |
11 | 5573724433 |
12 | 262b1a2193 |
13 | 12c328b912 |
14 | 8b519a2ab |
15 | 511a26833 |
hex | 3071fb47f |
13004420223 has 4 divisors (see below), whose sum is σ = 17339226968. Its totient is φ = 8669613480.
The previous prime is 13004420203. The next prime is 13004420227. The reversal of 13004420223 is 32202440031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13004420223 - 210 = 13004419199 is a prime.
It is a super-2 number, since 2×130044202232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13004420223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13004420227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167403368 + ... + 2167403373.
It is an arithmetic number, because the mean of its divisors is an integer number (4334806742).
Almost surely, 213004420223 is an apocalyptic number.
13004420223 is a deficient number, since it is larger than the sum of its proper divisors (4334806745).
13004420223 is an equidigital number, since it uses as much as digits as its factorization.
13004420223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4334806744.
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 13004420223 its reverse (32202440031), we get a palindrome (45206860254).
The spelling of 13004420223 in words is "thirteen billion, four million, four hundred twenty thousand, two hundred twenty-three".
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