Base | Representation |
---|---|
bin | 11000001110001111… |
… | …11110100000011001 |
3 | 1020120022010122222201 |
4 | 30013013332200121 |
5 | 203113113332213 |
6 | 5550230050201 |
7 | 640155601045 |
oct | 140707764031 |
9 | 36508118881 |
10 | 13004433433 |
11 | 5573733352 |
12 | 262b1a9961 |
13 | 12c3294934 |
14 | 8b51a1025 |
15 | 511a2a6dd |
hex | 3071fe819 |
13004433433 has 4 divisors (see below), whose sum is σ = 13004696628. Its totient is φ = 13004170240.
The previous prime is 13004433419. The next prime is 13004433437. The reversal of 13004433433 is 33433440031.
It is a happy number.
13004433433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33433440031 = 17 ⋅1966672943.
It can be written as a sum of positive squares in 2 ways, for example, as 6963568704 + 6040864729 = 83448^2 + 77723^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004433433 - 225 = 12970879001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13004433437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32716 + ... + 164557.
It is an arithmetic number, because the mean of its divisors is an integer number (3251174157).
Almost surely, 213004433433 is an apocalyptic number.
It is an amenable number.
13004433433 is a deficient number, since it is larger than the sum of its proper divisors (263195).
13004433433 is an equidigital number, since it uses as much as digits as its factorization.
13004433433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263194.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 13004433433 its reverse (33433440031), we get a palindrome (46437873464).
The spelling of 13004433433 in words is "thirteen billion, four million, four hundred thirty-three thousand, four hundred thirty-three".
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