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13004440011241 = 740930791475233
BaseRepresentation
bin1011110100111101010100…
…0001110000000111101001
31201001012201210011110200021
42331033111001300013221
53201031043120324431
643354053545240441
72511353101152520
oct275172501600751
951035653143607
1013004440011241
1141641743a7978
121560420793121
1373440c7ba0c3
1432d5bd9974b7
1517841e375b11
hexbd3d50701e9

13004440011241 has 16 divisors (see below), whose sum is σ = 14903403961600. Its totient is φ = 11115790507008.

The previous prime is 13004440011217. The next prime is 13004440011341. The reversal of 13004440011241 is 14211004440031.

13004440011241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13004440011241 - 25 = 13004440011209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13004440011341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8077561 + ... + 9552793.

It is an arithmetic number, because the mean of its divisors is an integer number (931462747600).

Almost surely, 213004440011241 is an apocalyptic number.

It is an amenable number.

13004440011241 is a deficient number, since it is larger than the sum of its proper divisors (1898963950359).

13004440011241 is a wasteful number, since it uses less digits than its factorization.

13004440011241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1478728.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13004440011241 its reverse (14211004440031), we get a palindrome (27215444451272).

The spelling of 13004440011241 in words is "thirteen trillion, four billion, four hundred forty million, eleven thousand, two hundred forty-one".

Divisors: 1 7 409 2863 3079 21553 1259311 1475233 8815177 10326631 603370297 4223592079 4542242407 31795696849 1857777144463 13004440011241