13004443 has 4 divisors (see below), whose sum is σ = 13011840. Its totient is φ = 12997048.

The previous prime is 13004393. The next prime is 13004449. The reversal of 13004443 is 34440031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 34440031 = 131 ⋅262901.

It is a cyclic number.

It is not a de Polignac number, because 13004443 - 2¹³ = 12996251 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13004443.

It is not an unprimeable number, because it can be changed into a prime (13004449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 621 + ... + 5137.

It is an arithmetic number, because the mean of its divisors is an integer number (3252960).

Almost surely, 2^13004443 is an apocalyptic number.

13004443 is a deficient number, since it is larger than the sum of its proper divisors (7397).

13004443 is an equidigital number, since it uses as much as digits as its factorization.

13004443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7396.

The product of its (nonzero) digits is 576, while the sum is 19.

The square root of 13004443 is about 3606.1673560721. The cubic root of 13004443 is about 235.1602528492.

Adding to 13004443 its reverse (34440031), we get a palindrome (47444474).

The spelling of 13004443 in words is "thirteen million, four thousand, four hundred forty-three".