Base | Representation |
---|---|
bin | 1011110100111101100101… |
… | …0101100101101110010010 |
3 | 1201001012220211020011012100 |
4 | 2331033121111211232102 |
5 | 3201031220123223102 |
6 | 43354105051141230 |
7 | 2511354636604431 |
oct | 275173125455622 |
9 | 51035824204170 |
10 | 13004512320402 |
11 | 41642011a5909 |
12 | 1560440a44816 |
13 | 7344217869a5 |
14 | 32d5c941b118 |
15 | 1784258aaa1c |
hex | bd3d9565b92 |
13004512320402 has 12 divisors (see below), whose sum is σ = 28176443360910. Its totient is φ = 4334837440128.
The previous prime is 13004512320391. The next prime is 13004512320413. The reversal of 13004512320402 is 20402321540031.
13004512320402 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 451 + 2 + 3 + 204 + 0 + 2 = 666.
It is an interprime number because it is at equal distance from previous prime (13004512320391) and next prime (13004512320413).
It can be written as a sum of positive squares in only one way, i.e., 11445832482561 + 1558679837841 = 3383169^2 + 1248471^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 361236453327 + ... + 361236453362.
Almost surely, 213004512320402 is an apocalyptic number.
13004512320402 is an abundant number, since it is smaller than the sum of its proper divisors (15171931040508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004512320402 is a wasteful number, since it uses less digits than its factorization.
13004512320402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 722472906697 (or 722472906694 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 13004512320402 its reverse (20402321540031), we get a palindrome (33406833860433).
The spelling of 13004512320402 in words is "thirteen trillion, four billion, five hundred twelve million, three hundred twenty thousand, four hundred two".
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