Base | Representation |
---|---|
bin | 1011110100111110011001… |
… | …1100101111111111000011 |
3 | 1201001020111011011100012012 |
4 | 2331033212130233333003 |
5 | 3201032142432120001 |
6 | 43354142550123135 |
7 | 2511363250451135 |
oct | 275174634577703 |
9 | 51036434140165 |
10 | 13004732301251 |
11 | 4164304395769 |
12 | 15604a26504ab |
13 | 734458218782 |
14 | 32d60a721055 |
15 | 178439d602bb |
hex | bd3e672ffc3 |
13004732301251 has 4 divisors (see below), whose sum is σ = 13004746709472. Its totient is φ = 13004717893032.
The previous prime is 13004732301203. The next prime is 13004732301313. The reversal of 13004732301251 is 15210323740031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13004732301251 - 218 = 13004732039107 is a prime.
It is a super-2 number, since 2×130047323012512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13004732301551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5752760 + ... + 7687893.
It is an arithmetic number, because the mean of its divisors is an integer number (3251186677368).
Almost surely, 213004732301251 is an apocalyptic number.
13004732301251 is a deficient number, since it is larger than the sum of its proper divisors (14408221).
13004732301251 is an equidigital number, since it uses as much as digits as its factorization.
13004732301251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14408220.
The product of its (nonzero) digits is 15120, while the sum is 32.
The spelling of 13004732301251 in words is "thirteen trillion, four billion, seven hundred thirty-two million, three hundred one thousand, two hundred fifty-one".
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