Search a number
-
+
13004947 = 47893109
BaseRepresentation
bin110001100111…
…000010010011
3220110201102201
4301213002103
511312124242
61142424031
7215353204
oct61470223
926421381
1013004947
11738289a
124432017
132904547
141a275ab
15121d4b7
hexc67093

13004947 has 8 divisors (see below), whose sum is σ = 13435200. Its totient is φ = 12581184.

The previous prime is 13004941. The next prime is 13004969. The reversal of 13004947 is 74940031.

13004947 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004947 - 23 = 13004939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2629 + ... + 5737.

It is an arithmetic number, because the mean of its divisors is an integer number (1679400).

Almost surely, 213004947 is an apocalyptic number.

13004947 is a deficient number, since it is larger than the sum of its proper divisors (430253).

13004947 is an equidigital number, since it uses as much as digits as its factorization.

13004947 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3245.

The product of its (nonzero) digits is 3024, while the sum is 28.

The square root of 13004947 is about 3606.2372356793. The cubic root of 13004947 is about 235.1632907657.

Adding to 13004947 its reverse (74940031), we get a palindrome (87944978).

The spelling of 13004947 in words is "thirteen million, four thousand, nine hundred forty-seven".

Divisors: 1 47 89 3109 4183 146123 276701 13004947