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13005000340151 = 17491743525261
BaseRepresentation
bin1011110100111111011001…
…1011001111001010110111
31201001021011211112010102212
42331033312123033022313
53201033220041341101
643354225323124035
72511403013653511
oct275176633171267
951037154463385
1013005000340151
11416443171a316
12156055837361b
1373449b905a81
1432d634174bb1
151784536591bb
hexbd3f66cf2b7

13005000340151 has 4 divisors (see below), whose sum is σ = 13005743882904. Its totient is φ = 13004256797400.

The previous prime is 13005000340067. The next prime is 13005000340193. The reversal of 13005000340151 is 15104300050031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13005000340151 - 210 = 13005000339127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13005000360151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371745140 + ... + 371780121.

It is an arithmetic number, because the mean of its divisors is an integer number (3251435970726).

Almost surely, 213005000340151 is an apocalyptic number.

13005000340151 is a deficient number, since it is larger than the sum of its proper divisors (743542753).

13005000340151 is an equidigital number, since it uses as much as digits as its factorization.

13005000340151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 743542752.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 13005000340151 its reverse (15104300050031), we get a palindrome (28109300390182).

The spelling of 13005000340151 in words is "thirteen trillion, five billion, three hundred forty thousand, one hundred fifty-one".

Divisors: 1 17491 743525261 13005000340151