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1300502114 = 2650251057
BaseRepresentation
bin100110110000100…
…0001011001100010
310100122010100111222
41031201001121202
510130412031424
6333014135042
744141041232
oct11541013142
93318110458
101300502114
1160811053a
12303651482
131795826a2
14c4a11cc2
157928de5e
hex4d841662

1300502114 has 4 divisors (see below), whose sum is σ = 1950753174. Its totient is φ = 650251056.

The previous prime is 1300502113. The next prime is 1300502123. The reversal of 1300502114 is 4112050031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4112050031 = 9714234861.

It can be written as a sum of positive squares in only one way, i.e., 801739225 + 498762889 = 28315^2 + 22333^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1300502092 and 1300502101.

It is not an unprimeable number, because it can be changed into a prime (1300502113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325125527 + ... + 325125530.

Almost surely, 21300502114 is an apocalyptic number.

1300502114 is a deficient number, since it is larger than the sum of its proper divisors (650251060).

1300502114 is an equidigital number, since it uses as much as digits as its factorization.

1300502114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 650251059.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1300502114 is about 36062.4751507713. The cubic root of 1300502114 is about 1091.5333787296.

Adding to 1300502114 its reverse (4112050031), we get a palindrome (5412552145).

The spelling of 1300502114 in words is "one billion, three hundred million, five hundred two thousand, one hundred fourteen".

Divisors: 1 2 650251057 1300502114